While fishing, you get bored and start to swing a sinker weight around in a circle below you on a 0.23 m piece

While fishing, you get bored and start to swing a sinker weight around in a circle below you on a 0.23 m piece of fishing line. The weight makes a complete circle every 0.60 s. What is the angle that the fishing line makes with the vertical?





I had 88.8 degrees but that is not the right answer to this problem. Please help.|||length of fishing line 0.23 m is hypoteneus of right angelled triangle in vertical plane with base equal to radius 'r' of circle





Suppose in the vector triangle of forces, fishing line length Lrepresents tension in the line





If height 'h' of triangle represents weight 'mg' of sinker and base 'r' of triangle represents centripetal force F=mv^/r=mr*4*(pi)^2 / T^2





where T is time period =0.60 s





mg/h=mr4(pi)^2/rT^2





h=gT^2/4(pi^2)=9.8*0.6*0.6 / 4*9.87= 0.089 m





suppose fishing line makes angle O with vertical ,then





cosO=h/ L( lenght of line)





cosO=0.089/0.23=0.3885





O=67.13 degree





Angle O with vertical is 67.13 degree|||It wouldn't be vertical. It would be "diagonal." and that is why


I would never have you in a boat with me, because, I would


end up with that hook in my eye. %26lt;}:-})